What are the solutions to the equation 9x^2+12x-6=x^2-7 ?

The solutions to the equation 9x^2+12x-6=x^2-7 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4

Find the zeros of 9x^2+12x-6=x^2-7

The zeros of 9x^2+12x-6=x^2-7 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4

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9 x^{2} + 12 x - 6 = x^{2} - 7

x = \frac{- 3 + 7}{4}, x = - \frac{3 + 7}{4}

Decimal Notation

x = - 0.08856 \dots, x = - 1.41143 \dots

Solution steps

9 x^{2} + 12 x - 6 = x^{2} - 7

Move

7

to the left side

9 x^{2} + 12 x + 1 = x^{2}

Move

x^{2}

to the left side

8 x^{2} + 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

1 2^{2} - 4 \cdot 8 \cdot 1 = 47

x_{1, 2} = \frac{- 12 \pm 4 7}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 12 + 4 7}{2 \cdot 8}, x_{2} = \frac{- 12 - 4 7}{2 \cdot 8}

x = \frac{- 12 + 4 7}{2 \cdot 8} : \frac{- 3 + 7}{4}

x = \frac{- 12 - 4 7}{2 \cdot 8} : - \frac{3 + 7}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 7}{4}, x = - \frac{3 + 7}{4}

G (x) = - 3 x^{2} + 102 x

y - 5 = \frac{1}{4} (y - 3)^{2}

x^{2} + x + 8 = 5

9 x^{2} - 15 x + 8 = 0

x^{2} - \frac{1}{2} x + \frac{1}{4} = 0

What are the solutions to the equation 9x^2+12x-6=x^2-7 ?
The solutions to the equation 9x^2+12x-6=x^2-7 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4
Find the zeros of 9x^2+12x-6=x^2-7
The zeros of 9x^2+12x-6=x^2-7 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4