What are the solutions to the equation s^2+20s+200=0 ?

The solutions to the equation s^2+20s+200=0 are s=-10+10i,s=-10-10i

Find the zeros of s^2+20s+200=0

The zeros of s^2+20s+200=0 are s=-10+10i,s=-10-10i

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s^{2} + 20 s + 200 = 0

s = - 10 + 10 i, s = - 10 - 10 i

Solution steps

s^{2} + 20 s + 200 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 200 : 20 i

s_{1, 2} = \frac{- 20 \pm 20 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 20 + 20 i}{2 \cdot 1}, s_{2} = \frac{- 20 - 20 i}{2 \cdot 1}

s = \frac{- 20 + 20 i}{2 \cdot 1} : - 10 + 10 i

s = \frac{- 20 - 20 i}{2 \cdot 1} : - 10 - 10 i

The solutions to the quadratic equation are:

s = - 10 + 10 i, s = - 10 - 10 i

x^{2} = 3 x^{2} - 98

w^{2} + 2 w - 15 = 0

4 x^{2} + 8 x - 6 = 0

x^{2} + 2 x + 5 x + 10 - 5 x + 10 = 28

180 = - 16 t^{2} + 120 t

What are the solutions to the equation s^2+20s+200=0 ?
The solutions to the equation s^2+20s+200=0 are s=-10+10i,s=-10-10i
Find the zeros of s^2+20s+200=0
The zeros of s^2+20s+200=0 are s=-10+10i,s=-10-10i