What are the solutions to the equation (k+d-b)^2=a ?

The solutions to the equation (k+d-b)^2=a are k=sqrt(a)-d+b,k=-sqrt(a)-d+b

Find the zeros of (k+d-b)^2=a

The zeros of (k+d-b)^2=a are k=sqrt(a)-d+b,k=-sqrt(a)-d+b

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(k + d - b)^{2} = a

k = a - d + b, k = - a - d + b

Solution steps

(k + d - b)^{2} = a

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + d - b = a : k = a - d + b

Solve

k + d - b = - a : k = - a - d + b

The solutions to the quadratic equation are:

k = a - d + b, k = - a - d + b

2 x^{2} - 1 = 1

(x + 6)^{2} - 2 = 5

6 x^{2} + 19 x + 14 = 0

w^{2} + 9 w + 18 = 0

\frac{3}{4} x^{2} - 3 = 0

What are the solutions to the equation (k+d-b)^2=a ?
The solutions to the equation (k+d-b)^2=a are k=sqrt(a)-d+b,k=-sqrt(a)-d+b
Find the zeros of (k+d-b)^2=a
The zeros of (k+d-b)^2=a are k=sqrt(a)-d+b,k=-sqrt(a)-d+b