What are the solutions to the equation 25x^2-90x+81=0 ?

The solutions to the equation 25x^2-90x+81=0 are x= 9/5

Find the zeros of 25x^2-90x+81=0

The zeros of 25x^2-90x+81=0 are x= 9/5

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25 x^{2} - 90 x + 81 = 0

x = \frac{9}{5}

Decimal Notation

x = 1.8

Solution steps

25 x^{2} - 90 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 90 ) \pm ( - 90 ) ^{2} - 4 \cdot 25 \cdot 81}{2 \cdot 25}

(- 90)^{2} - 4 \cdot 25 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 90 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 90 )}{2 \cdot 25}

\frac{- ( - 90 )}{2 \cdot 25} = \frac{9}{5}

x = \frac{9}{5}

The solution to the quadratic equation is:

x = \frac{9}{5}

9 x^{2} = 12 x - 5

x^{2} + 14 x + 96 = 0

(x + 10)^{2} = 0

x^{2} + 8 x - 5 = 15

x^{2} + x + 3 = 5

What are the solutions to the equation 25x^2-90x+81=0 ?
The solutions to the equation 25x^2-90x+81=0 are x= 9/5
Find the zeros of 25x^2-90x+81=0
The zeros of 25x^2-90x+81=0 are x= 9/5