What are the solutions to the equation solvefor a,(a^2-b^2)/9 =a+b ?

The solutions to the equation solvefor a,(a^2-b^2)/9 =a+b are a=-b,a=b+9

Find the zeros of solvefor a,(a^2-b^2)/9 =a+b

The zeros of solvefor a,(a^2-b^2)/9 =a+b are a=-b,a=b+9

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solve for

a, \frac{a ^{2} - b ^{2}}{9} = a + b

a = - b, a = b + 9

Solution steps

\frac{a ^{2} - b ^{2}}{9} = a + b

Multiply both sides by

9

a^{2} - b^{2} = 9 a + 9 b

Move

9 b

to the left side

a^{2} - b^{2} - 9 b = 9 a

Move

9 a

to the left side

a^{2} - b^{2} - 9 b - 9 a = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 9 a - b^{2} - 9 b = 0

Factor

a^{2} - 9 a - b^{2} - 9 b : (a + b) (a - b - 9)

(a + b) (a - b - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + b = 0 or a - b - 9 = 0

Solve

a + b = 0 : a = - b

Solve

a - b - 9 = 0 : a = b + 9

The solutions to the quadratic equation are:

a = - b, a = b + 9

3 x^{2} + \frac{4 ( 3 x + 1 )}{3} = 0

5 n^{2} - 6 n - 27 = 0

x^{2} - a^{2} - b x - ab = 0

(x + 4) (x - 2) = 8

(x - 1)^{2} + 15 = 14

What are the solutions to the equation solvefor a,(a^2-b^2)/9 =a+b ?
The solutions to the equation solvefor a,(a^2-b^2)/9 =a+b are a=-b,a=b+9
Find the zeros of solvefor a,(a^2-b^2)/9 =a+b
The zeros of solvefor a,(a^2-b^2)/9 =a+b are a=-b,a=b+9