What are the solutions to the equation 9n^2-5=-99 ?

The solutions to the equation 9n^2-5=-99 are n=(sqrt(94))/3 i,n=-(sqrt(94))/3 i

Find the zeros of 9n^2-5=-99

The zeros of 9n^2-5=-99 are n=(sqrt(94))/3 i,n=-(sqrt(94))/3 i

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9 n^{2} - 5 = - 99

n = \frac{94}{3} i, n = - \frac{94}{3} i

Solution steps

9 n^{2} - 5 = - 99

Move

5

to the right side

9 n^{2} = - 94

Divide both sides by

9

n^{2} = - \frac{94}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - \frac{94}{9}, n = - - \frac{94}{9}

- \frac{94}{9} = \frac{94}{3} i

- - \frac{94}{9} = - \frac{94}{3} i

n = \frac{94}{3} i, n = - \frac{94}{3} i

n^{2} = 1

4 u^{2} + 9 = - 12 u

3 k^{2} + k - 1 = 0

(4 - 2 y)^{2} + 4 y^{2} = 16

x^{2} + 15 x + 39 = 0

What are the solutions to the equation 9n^2-5=-99 ?
The solutions to the equation 9n^2-5=-99 are n=(sqrt(94))/3 i,n=-(sqrt(94))/3 i
Find the zeros of 9n^2-5=-99
The zeros of 9n^2-5=-99 are n=(sqrt(94))/3 i,n=-(sqrt(94))/3 i