What are the solutions to the equation (x-3)(x-2)=20 ?

The solutions to the equation (x-3)(x-2)=20 are x=7,x=-2

Find the zeros of (x-3)(x-2)=20

The zeros of (x-3)(x-2)=20 are x=7,x=-2

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(x - 3) (x - 2) = 20

x = 7, x = - 2

Solution steps

(x - 3) (x - 2) = 20

Expand

(x - 3) (x - 2) : x^{2} - 5 x + 6

x^{2} - 5 x + 6 = 20

Move

20

to the left side

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

6 - 7 x = 3 x^{2}

n^{2} + 19 n + 66 = 6

w, m w^{2} = \frac{9 k \pm 41 k}{4}

0.9 \cdot 0.85 \cdot 210 \cdot 10 \cdot x \cdot (17 - 0.5 \cdot x) = 0.88 \cdot 1 0^{5}

\frac{1}{2} x^{2} - 11 = 25

What are the solutions to the equation (x-3)(x-2)=20 ?
The solutions to the equation (x-3)(x-2)=20 are x=7,x=-2
Find the zeros of (x-3)(x-2)=20
The zeros of (x-3)(x-2)=20 are x=7,x=-2