What are the solutions to the equation -3x^2+3x+6=0 ?

The solutions to the equation -3x^2+3x+6=0 are x=-1,x=2

Find the zeros of -3x^2+3x+6=0

The zeros of -3x^2+3x+6=0 are x=-1,x=2

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- 3 x^{2} + 3 x + 6 = 0

x = - 1, x = 2

Solution steps

- 3 x^{2} + 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 6}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 6 = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 ( - 3 )}, x_{2} = \frac{- 3 - 9}{2 ( - 3 )}

x = \frac{- 3 + 9}{2 ( - 3 )} : - 1

x = \frac{- 3 - 9}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

- x^{2} + x = 1

3 x^{2} = - 2 x

2 x^{2} - 12 x + 17 = 0

3 x^{2} = - 3 x

(3 + 23) (23) = (2 x) (x)

What are the solutions to the equation -3x^2+3x+6=0 ?
The solutions to the equation -3x^2+3x+6=0 are x=-1,x=2
Find the zeros of -3x^2+3x+6=0
The zeros of -3x^2+3x+6=0 are x=-1,x=2