What are the solutions to the equation x(2x-7)-4x+14=0 ?

The solutions to the equation x(2x-7)-4x+14=0 are x= 7/2 ,x=2

Find the zeros of x(2x-7)-4x+14=0

The zeros of x(2x-7)-4x+14=0 are x= 7/2 ,x=2

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x (2 x - 7) - 4 x + 14 = 0

x = \frac{7}{2}, x = 2

Decimal Notation

x = 3.5, x = 2

Solution steps

x (2 x - 7) - 4 x + 14 = 0

Expand

x (2 x - 7) - 4 x + 14 : 2 x^{2} - 11 x + 14

2 x^{2} - 11 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 14 = 3

x_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 2}

x = \frac{- ( - 11 ) + 3}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 11 ) - 3}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 2

(x + 4) (x - 2) = 27

- x^{2} + 6 x + 5 = 0

x, f = x^{2} yz - x y z^{3}

x^{2} + 2 x + 50 = 0

a^{2} = a + 12

What are the solutions to the equation x(2x-7)-4x+14=0 ?
The solutions to the equation x(2x-7)-4x+14=0 are x= 7/2 ,x=2
Find the zeros of x(2x-7)-4x+14=0
The zeros of x(2x-7)-4x+14=0 are x= 7/2 ,x=2