What are the solutions to the equation 17=(x-5)^2-1 ?

The solutions to the equation 17=(x-5)^2-1 are x=3sqrt(2)+5,x=-3sqrt(2)+5

Find the zeros of 17=(x-5)^2-1

The zeros of 17=(x-5)^2-1 are x=3sqrt(2)+5,x=-3sqrt(2)+5

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17 = (x - 5)^{2} - 1

x = 32 + 5, x = - 32 + 5

Decimal Notation

x = 9.24264 \dots, x = 0.75735 \dots

Solution steps

17 = (x - 5)^{2} - 1

Switch sides

(x - 5)^{2} - 1 = 17

Move

1

to the right side

(x - 5)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 18 : x = 32 + 5

Solve

x - 5 = - 18 : x = - 32 + 5

The solutions to the quadratic equation are:

x = 32 + 5, x = - 32 + 5

d^{2} = 11 d - 10

8 x^{2} - 9 = x^{2} - 2

7 x^{2} = 10 x - 3

x^{2} + x - 2 = 4

8 = 2.4 t - 0.1 t^{2}

What are the solutions to the equation 17=(x-5)^2-1 ?
The solutions to the equation 17=(x-5)^2-1 are x=3sqrt(2)+5,x=-3sqrt(2)+5
Find the zeros of 17=(x-5)^2-1
The zeros of 17=(x-5)^2-1 are x=3sqrt(2)+5,x=-3sqrt(2)+5