What are the solutions to the equation (D+2/25)x^1-1/50 x^2=0 ?

The solutions to the equation (D+2/25)x^1-1/50 x^2=0 are x=0,x=50D+4

Find the zeros of (D+2/25)x^1-1/50 x^2=0

The zeros of (D+2/25)x^1-1/50 x^2=0 are x=0,x=50D+4

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(D + \frac{2}{25}) x^{1} - \frac{1}{50} x^{2} = 0

x = 0, x = 50 D + 4

Solution steps

(D + \frac{2}{25}) x^{1} - \frac{1}{50} x^{2} = 0

Multiply both sides by

50

50 x (D + \frac{2}{25}) - x^{2} = 0

Expand

50 x (D + \frac{2}{25}) - x^{2} : 50 D x + 4 x - x^{2}

50 D x + 4 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + (50 D + 4) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 50 D + 4 ) \pm ( 50 D + 4 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

Simplify

(50 D + 4)^{2} - 4 (- 1) \cdot 0 : 50 D + 4

x_{1, 2} = \frac{- ( 50 D + 4 ) \pm ( 50 D + 4 )}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( 50 D + 4 ) + 50 D + 4}{2 ( - 1 )}, x_{2} = \frac{- ( 50 D + 4 ) - ( 50 D + 4 )}{2 ( - 1 )}

x = \frac{- ( 50 D + 4 ) + 50 D + 4}{2 ( - 1 )} : 0

x = \frac{- ( 50 D + 4 ) - ( 50 D + 4 )}{2 ( - 1 )} : 50 D + 4

The solutions to the quadratic equation are:

x = 0, x = 50 D + 4

x^{2} - 6 x - 11

x^{2} - 6 x - 16

- 0.002 x^{2} + 0.37 x = 8

x, 4 x^{2} + 6 x y - 3 y + 4 = 0

x, y = 1 - x^{2}

What are the solutions to the equation (D+2/25)x^1-1/50 x^2=0 ?
The solutions to the equation (D+2/25)x^1-1/50 x^2=0 are x=0,x=50D+4
Find the zeros of (D+2/25)x^1-1/50 x^2=0
The zeros of (D+2/25)x^1-1/50 x^2=0 are x=0,x=50D+4