What are the solutions to the equation 3x^2-8x-21=0 ?

The solutions to the equation 3x^2-8x-21=0 are x=(4+sqrt(79))/3 ,x=(4-sqrt(79))/3

Find the zeros of 3x^2-8x-21=0

The zeros of 3x^2-8x-21=0 are x=(4+sqrt(79))/3 ,x=(4-sqrt(79))/3

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3 x^{2} - 8 x - 21 = 0

x = \frac{4 + 79}{3}, x = \frac{4 - 79}{3}

Decimal Notation

x = 4.29606 \dots, x = - 1.62939 \dots

Solution steps

3 x^{2} - 8 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 21 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 21) = 279

x_{1, 2} = \frac{- ( - 8 ) \pm 2 79}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 79}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 79}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 79}{2 \cdot 3} : \frac{4 + 79}{3}

x = \frac{- ( - 8 ) - 2 79}{2 \cdot 3} : \frac{4 - 79}{3}

The solutions to the quadratic equation are:

x = \frac{4 + 79}{3}, x = \frac{4 - 79}{3}

9 - 3 x^{2} + 5 x - 8 + 7 x^{2} = 5 x^{2} - 9 + 4 x + 4 x

405 - 168 x + 12 x^{2} = 0

0 = x^{2} - 6 x - 16

x^{2} - 6 x + 18

x^{2} - 6 x + 25

What are the solutions to the equation 3x^2-8x-21=0 ?
The solutions to the equation 3x^2-8x-21=0 are x=(4+sqrt(79))/3 ,x=(4-sqrt(79))/3
Find the zeros of 3x^2-8x-21=0
The zeros of 3x^2-8x-21=0 are x=(4+sqrt(79))/3 ,x=(4-sqrt(79))/3