What are the solutions to the equation solvefor x,2x^2+5x+2=0 ?

The solutions to the equation solvefor x,2x^2+5x+2=0 are x=-1/2 ,x=-2

Find the zeros of solvefor x,2x^2+5x+2=0

The zeros of solvefor x,2x^2+5x+2=0 are x=-1/2 ,x=-2

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x, 2 x^{2} + 5 x + 2 = 0

x = - \frac{1}{2}, x = - 2

Decimal

x = - 0.5, x = - 2

Solution steps

2 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 2}, x_{2} = \frac{- 5 - 3}{2 \cdot 2}

x = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 2

3 x^{2} + 2 = - 62

5 x^{2} - 2 x + 2 = 0

x^{2} + (\frac{1}{3})^{2} = 1

0.1 x (1 - \frac{x}{800}) - 0.05 x = 0

(x + a) (x + b) = 0

What are the solutions to the equation solvefor x,2x^2+5x+2=0 ?
The solutions to the equation solvefor x,2x^2+5x+2=0 are x=-1/2 ,x=-2
Find the zeros of solvefor x,2x^2+5x+2=0
The zeros of solvefor x,2x^2+5x+2=0 are x=-1/2 ,x=-2