What are the solutions to the equation 2m^2+13m+20=0 ?

The solutions to the equation 2m^2+13m+20=0 are m=-5/2 ,m=-4

Find the zeros of 2m^2+13m+20=0

The zeros of 2m^2+13m+20=0 are m=-5/2 ,m=-4

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2 m^{2} + 13 m + 20 = 0

m = - \frac{5}{2}, m = - 4

Decimal Notation

m = - 2.5, m = - 4

Solution steps

2 m^{2} + 13 m + 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 20 = 3

m_{1, 2} = \frac{- 13 \pm 3}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 13 + 3}{2 \cdot 2}, m_{2} = \frac{- 13 - 3}{2 \cdot 2}

m = \frac{- 13 + 3}{2 \cdot 2} : - \frac{5}{2}

m = \frac{- 13 - 3}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

m = - \frac{5}{2}, m = - 4

2 x^{2} - \frac{1}{2} = 0

- 4 x^{2} + 6 x - 16 = - 5 x^{2}

x^{2} - 10 x + 27

x^{2} - 10 x + 18

t, p = 25 t^{2} + 72 t + 100

What are the solutions to the equation 2m^2+13m+20=0 ?
The solutions to the equation 2m^2+13m+20=0 are m=-5/2 ,m=-4
Find the zeros of 2m^2+13m+20=0
The zeros of 2m^2+13m+20=0 are m=-5/2 ,m=-4