What are the solutions to the equation 2x^2-x+15=0 ?

The solutions to the equation 2x^2-x+15=0 are x= 1/4+i(sqrt(119))/4 ,x= 1/4-i(sqrt(119))/4

Find the zeros of 2x^2-x+15=0

The zeros of 2x^2-x+15=0 are x= 1/4+i(sqrt(119))/4 ,x= 1/4-i(sqrt(119))/4

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2 x^{2} - x + 15 = 0

x = \frac{1}{4} + i \frac{119}{4}, x = \frac{1}{4} - i \frac{119}{4}

Solution steps

2 x^{2} - x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 15 : 119 i

x_{1, 2} = \frac{- ( - 1 ) \pm 119 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 119 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 119 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 119 i}{2 \cdot 2} : \frac{1}{4} + i \frac{119}{4}

x = \frac{- ( - 1 ) - 119 i}{2 \cdot 2} : \frac{1}{4} - i \frac{119}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{119}{4}, x = \frac{1}{4} - i \frac{119}{4}

8^{2} + 3^{2} = x^{2}

y^{2} + 2 y = 8

- 3 x^{2} - 15 x + 2250 = 0

2 q^{2} + 14 q - 5 = 0

180 x - 3 x^{2} = 0

What are the solutions to the equation 2x^2-x+15=0 ?
The solutions to the equation 2x^2-x+15=0 are x= 1/4+i(sqrt(119))/4 ,x= 1/4-i(sqrt(119))/4
Find the zeros of 2x^2-x+15=0
The zeros of 2x^2-x+15=0 are x= 1/4+i(sqrt(119))/4 ,x= 1/4-i(sqrt(119))/4