What are the solutions to the equation quadraticformula x^2+16=-12x ?

The solutions to the equation quadraticformula x^2+16=-12x are x=2(sqrt(5)-3),x=-2(3+sqrt(5))

Find the zeros of quadraticformula x^2+16=-12x

The zeros of quadraticformula x^2+16=-12x are x=2(sqrt(5)-3),x=-2(3+sqrt(5))

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x^{2} + 16 = - 12 x

x = 2 (5 - 3), x = - 2 (3 + 5)

Decimal Notation

x = - 1.52786 \dots, x = - 10.47213 \dots

Solution steps

x^{2} + 16 = - 12 x

Move

12 x

to the left side

x^{2} + 16 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 12 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 16 = 45

x_{1, 2} = \frac{- 12 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 5}{2 \cdot 1}

x = \frac{- 12 + 4 5}{2 \cdot 1} : 2 (5 - 3)

x = \frac{- 12 - 4 5}{2 \cdot 1} : - 2 (3 + 5)

The solutions to the quadratic equation are:

x = 2 (5 - 3), x = - 2 (3 + 5)

4 x^{2} - 6 x - 18 = 0

a^{2} + 8 a = 0

4 y^{2} = - y + 3

10 x^{2} - 31 x + 15 = 0

(x + 1)^{2} + (x - 2)^{2} = 10

What are the solutions to the equation quadraticformula x^2+16=-12x ?
The solutions to the equation quadraticformula x^2+16=-12x are x=2(sqrt(5)-3),x=-2(3+sqrt(5))
Find the zeros of quadraticformula x^2+16=-12x
The zeros of quadraticformula x^2+16=-12x are x=2(sqrt(5)-3),x=-2(3+sqrt(5))