What are the solutions to the equation 9-x^2-x-3=0 ?

The solutions to the equation 9-x^2-x-3=0 are x=-3,x=2

Find the zeros of 9-x^2-x-3=0

The zeros of 9-x^2-x-3=0 are x=-3,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 - x^{2} - x - 3 = 0

x = - 3, x = 2

Solution steps

9 - x^{2} - x - 3 = 0

Refine

- x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 6 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - 3

x = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 3, x = 2

2 x^{2} - 7 x = 3

2 x^{2} - 7 x = 9

3 r^{2} + 2 r - 1 = 0

4 x^{2} - 8 x + 16 = 0

- x^{2} - 8 x = 16

What are the solutions to the equation 9-x^2-x-3=0 ?
The solutions to the equation 9-x^2-x-3=0 are x=-3,x=2
Find the zeros of 9-x^2-x-3=0
The zeros of 9-x^2-x-3=0 are x=-3,x=2