What are the solutions to the equation completesquare 2x^2-4x=0 ?

The solutions to the equation completesquare 2x^2-4x=0 are x=2,x=0

Find the zeros of completesquare 2x^2-4x=0

The zeros of completesquare 2x^2-4x=0 are x=2,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 4 x = 0

x = 2, x = 0

Solution steps

2 x^{2} - 4 x = 0

Divide both sides by

2

\frac{2 x ^{2} - 4 x}{2} = \frac{0}{2}

x^{2} - 2 x = 0

Rewrite in the form

(x + a)^{2} = b

(x - 1)^{2} = 1

For

the solutions are

f (x) = a, - a

Solve

x - 1 = 1 : x = 2

Solve

x - 1 = - 1 : x = 0

The solutions to the quadratic equation are:

x = 2, x = 0

x^{2} + 12 x + c

x^{2} - \frac{15}{2} x + \frac{45}{4} = 0

6 x^{2} - 18 x - 108 = 0

x^{2} + 20 x + 19 = 0

- 25 x^{2} - 15 x = 0

What are the solutions to the equation completesquare 2x^2-4x=0 ?
The solutions to the equation completesquare 2x^2-4x=0 are x=2,x=0
Find the zeros of completesquare 2x^2-4x=0
The zeros of completesquare 2x^2-4x=0 are x=2,x=0