What are the solutions to the equation 49x^2-14x=6 ?

The solutions to the equation 49x^2-14x=6 are x=(1+sqrt(7))/7 ,x=(1-sqrt(7))/7

Find the zeros of 49x^2-14x=6

The zeros of 49x^2-14x=6 are x=(1+sqrt(7))/7 ,x=(1-sqrt(7))/7

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49 x^{2} - 14 x = 6

x = \frac{1 + 7}{7}, x = \frac{1 - 7}{7}

Decimal Notation

x = 0.52082 \dots, x = - 0.23510 \dots

Solution steps

49 x^{2} - 14 x = 6

Move

6

to the left side

49 x^{2} - 14 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 49 ( - 6 )}{2 \cdot 49}

(- 14)^{2} - 4 \cdot 49 (- 6) = 147

x_{1, 2} = \frac{- ( - 14 ) \pm 14 7}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14 7}{2 \cdot 49}, x_{2} = \frac{- ( - 14 ) - 14 7}{2 \cdot 49}

x = \frac{- ( - 14 ) + 14 7}{2 \cdot 49} : \frac{1 + 7}{7}

x = \frac{- ( - 14 ) - 14 7}{2 \cdot 49} : \frac{1 - 7}{7}

The solutions to the quadratic equation are:

x = \frac{1 + 7}{7}, x = \frac{1 - 7}{7}

y^{2} - 2 y - 5 = 0

a^{2} + 12 a + 32 = 0

5 x^{2} + 4 x - 57 = 0

3 x + 7 = x^{2} + 6 x - 3

4 x^{2} + 3 = - 8 x

What are the solutions to the equation 49x^2-14x=6 ?
The solutions to the equation 49x^2-14x=6 are x=(1+sqrt(7))/7 ,x=(1-sqrt(7))/7
Find the zeros of 49x^2-14x=6
The zeros of 49x^2-14x=6 are x=(1+sqrt(7))/7 ,x=(1-sqrt(7))/7