What are the solutions to the equation 0=-x^2+2x-1 ?

The solutions to the equation 0=-x^2+2x-1 are x=1

Find the zeros of 0=-x^2+2x-1

The zeros of 0=-x^2+2x-1 are x=1

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0 = - x^{2} + 2 x - 1

x = 1

Solution steps

0 = - x^{2} + 2 x - 1

Switch sides

- x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

2^{2} - 4 (- 1) (- 1) = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 ( - 1 )}

x = \frac{- 2}{2 ( - 1 )}

\frac{- 2}{2 ( - 1 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

x^{2} + (\frac{a}{a + b} + \frac{a + b}{a}) x + 1 = 0

3 x^{2} - x - 24 = 0

6 x^{2} - 8 x + 5 = 0

2 x^{2} - 8 x - 16 = 0

x^{2} + 12 x + 50 = 15

What are the solutions to the equation 0=-x^2+2x-1 ?
The solutions to the equation 0=-x^2+2x-1 are x=1
Find the zeros of 0=-x^2+2x-1
The zeros of 0=-x^2+2x-1 are x=1