What are the solutions to the equation 2x^2-12x-8=0 ?

The solutions to the equation 2x^2-12x-8=0 are x=3+sqrt(13),x=3-sqrt(13)

Find the zeros of 2x^2-12x-8=0

The zeros of 2x^2-12x-8=0 are x=3+sqrt(13),x=3-sqrt(13)

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2 x^{2} - 12 x - 8 = 0

x = 3 + 13, x = 3 - 13

Decimal Notation

x = 6.60555 \dots, x = - 0.60555 \dots

Solution steps

2 x^{2} - 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 8) = 413

x_{1, 2} = \frac{- ( - 12 ) \pm 4 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 13}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 4 13}{2 \cdot 2}

x = \frac{- ( - 12 ) + 4 13}{2 \cdot 2} : 3 + 13

x = \frac{- ( - 12 ) - 4 13}{2 \cdot 2} : 3 - 13

The solutions to the quadratic equation are:

x = 3 + 13, x = 3 - 13

a^{2} - 5 = 0

x, (x - 3)^{2} + (y + 6)^{2} = 0

x^{2} - 3 = 6 x + 10

8 x^{2} - 22 x - 21 = 0

x, y = x^{2} - 7 x + 12

What are the solutions to the equation 2x^2-12x-8=0 ?
The solutions to the equation 2x^2-12x-8=0 are x=3+sqrt(13),x=3-sqrt(13)
Find the zeros of 2x^2-12x-8=0
The zeros of 2x^2-12x-8=0 are x=3+sqrt(13),x=3-sqrt(13)