What are the solutions to the equation m^2-49/2 m= 1/2 ?

The solutions to the equation m^2-49/2 m= 1/2 are m=(49+sqrt(2409))/4 ,m=(49-sqrt(2409))/4

Find the zeros of m^2-49/2 m= 1/2

The zeros of m^2-49/2 m= 1/2 are m=(49+sqrt(2409))/4 ,m=(49-sqrt(2409))/4

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m^{2} - \frac{49}{2} m = \frac{1}{2}

m = \frac{49 + 2409}{4}, m = \frac{49 - 2409}{4}

Decimal Notation

m = 24.52039 \dots, m = - 0.02039 \dots

Solution steps

m^{2} - \frac{49}{2} m = \frac{1}{2}

Multiply both sides by

2

2 m^{2} - 49 m = 1

Move

1

to the left side

2 m^{2} - 49 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 49)^{2} - 4 \cdot 2 (- 1) = 2409

m_{1, 2} = \frac{- ( - 49 ) \pm 2409}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 49 ) + 2409}{2 \cdot 2}, m_{2} = \frac{- ( - 49 ) - 2409}{2 \cdot 2}

m = \frac{- ( - 49 ) + 2409}{2 \cdot 2} : \frac{49 + 2409}{4}

m = \frac{- ( - 49 ) - 2409}{2 \cdot 2} : \frac{49 - 2409}{4}

The solutions to the quadratic equation are:

m = \frac{49 + 2409}{4}, m = \frac{49 - 2409}{4}

a, y = (a x + b)^{2}

1 2^{2} + b^{2} = 3 7^{2}

12 + 1.6 x = 8 x - \frac{1}{5} x^{2}

(3 - x) (- 1 - x) + 4 = 0

(- 3 y)^{2} + y^{2} = 40

What are the solutions to the equation m^2-49/2 m= 1/2 ?
The solutions to the equation m^2-49/2 m= 1/2 are m=(49+sqrt(2409))/4 ,m=(49-sqrt(2409))/4
Find the zeros of m^2-49/2 m= 1/2
The zeros of m^2-49/2 m= 1/2 are m=(49+sqrt(2409))/4 ,m=(49-sqrt(2409))/4