What are the solutions to the equation 6x^2-x+6=0 ?

The solutions to the equation 6x^2-x+6=0 are x= 1/12+i(sqrt(143))/(12),x= 1/12-i(sqrt(143))/(12)

Find the zeros of 6x^2-x+6=0

The zeros of 6x^2-x+6=0 are x= 1/12+i(sqrt(143))/(12),x= 1/12-i(sqrt(143))/(12)

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6 x^{2} - x + 6 = 0

x = \frac{1}{12} + i \frac{143}{12}, x = \frac{1}{12} - i \frac{143}{12}

Solution steps

6 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

Simplify

(- 1)^{2} - 4 \cdot 6 \cdot 6 : 143 i

x_{1, 2} = \frac{- ( - 1 ) \pm 143 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 143 i}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 143 i}{2 \cdot 6}

x = \frac{- ( - 1 ) + 143 i}{2 \cdot 6} : \frac{1}{12} + i \frac{143}{12}

x = \frac{- ( - 1 ) - 143 i}{2 \cdot 6} : \frac{1}{12} - i \frac{143}{12}

The solutions to the quadratic equation are:

x = \frac{1}{12} + i \frac{143}{12}, x = \frac{1}{12} - i \frac{143}{12}

3 x^{2} - 48 x + 180 = 0

42 x^{2} - 36 x + 6 = 0

r, r^{2} + t^{2} = r (t)^{2}

x, 4 x^{2} - 25 y^{2} = 0

0.000003 x^{2} - 0.006 x + 6 = 0

What are the solutions to the equation 6x^2-x+6=0 ?
The solutions to the equation 6x^2-x+6=0 are x= 1/12+i(sqrt(143))/(12),x= 1/12-i(sqrt(143))/(12)
Find the zeros of 6x^2-x+6=0
The zeros of 6x^2-x+6=0 are x= 1/12+i(sqrt(143))/(12),x= 1/12-i(sqrt(143))/(12)