What are the solutions to the equation 15x^2+23x+4=0 ?

The solutions to the equation 15x^2+23x+4=0 are x=-1/5 ,x=-4/3

Find the zeros of 15x^2+23x+4=0

The zeros of 15x^2+23x+4=0 are x=-1/5 ,x=-4/3

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15 x^{2} + 23 x + 4 = 0

x = - \frac{1}{5}, x = - \frac{4}{3}

Decimal Notation

x = - 0.2, x = - 1.33333 \dots

Solution steps

15 x^{2} + 23 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 15 \cdot 4}{2 \cdot 15}

2 3^{2} - 4 \cdot 15 \cdot 4 = 17

x_{1, 2} = \frac{- 23 \pm 17}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 23 + 17}{2 \cdot 15}, x_{2} = \frac{- 23 - 17}{2 \cdot 15}

x = \frac{- 23 + 17}{2 \cdot 15} : - \frac{1}{5}

x = \frac{- 23 - 17}{2 \cdot 15} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - \frac{4}{3}

9 (9 - 9 x^{2}) = 9

2 4^{2} + b^{2} = 4 0^{2}

2 x = 4 x^{2} - 1

\frac{4}{9} a^{2} - \frac{1}{4} a = 5

(5 + y)^{2} + y^{2} = 37

What are the solutions to the equation 15x^2+23x+4=0 ?
The solutions to the equation 15x^2+23x+4=0 are x=-1/5 ,x=-4/3
Find the zeros of 15x^2+23x+4=0
The zeros of 15x^2+23x+4=0 are x=-1/5 ,x=-4/3