What are the solutions to the equation (1-x)^2=4 ?

The solutions to the equation (1-x)^2=4 are x=-1,x=3

Find the zeros of (1-x)^2=4

The zeros of (1-x)^2=4 are x=-1,x=3

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(1 - x)^{2} = 4

x = - 1, x = 3

Solution steps

(1 - x)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - x = 4 : x = - 1

Solve

1 - x = - 4 : x = 3

The solutions to the quadratic equation are:

x = - 1, x = 3

m^{2} + 7 m = 0

x, f = I n (x^{2} + 10)

x^{2} - 4 x = - 20

b, c^{2} = a^{2} + b^{2}

- 5 x^{2} + 2 x - 1 = 0

What are the solutions to the equation (1-x)^2=4 ?
The solutions to the equation (1-x)^2=4 are x=-1,x=3
Find the zeros of (1-x)^2=4
The zeros of (1-x)^2=4 are x=-1,x=3