What are the solutions to the equation (3x+1)(x+5)=0 ?

The solutions to the equation (3x+1)(x+5)=0 are x=-1/3 ,x=-5

Find the zeros of (3x+1)(x+5)=0

The zeros of (3x+1)(x+5)=0 are x=-1/3 ,x=-5

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(3 x + 1) (x + 5) = 0

x = - \frac{1}{3}, x = - 5

Decimal Notation

x = - 0.33333 \dots, x = - 5

Solution steps

(3 x + 1) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or x + 5 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 5

5582.28 x^{2} + 81.42 x = 43200

x^{2} - 3 = 2 x - 4 x^{2} + 6

9 x^{2} + 32 = 3 x^{2} + 86

6 x^{2} + 8 x = 5 x^{2} - 1

(x - 6) x = 16

What are the solutions to the equation (3x+1)(x+5)=0 ?
The solutions to the equation (3x+1)(x+5)=0 are x=-1/3 ,x=-5
Find the zeros of (3x+1)(x+5)=0
The zeros of (3x+1)(x+5)=0 are x=-1/3 ,x=-5