What are the solutions to the equation -2x^2-5x+6=0 ?

The solutions to the equation -2x^2-5x+6=0 are x=-(5+sqrt(73))/4 ,x=(sqrt(73)-5)/4

Find the zeros of -2x^2-5x+6=0

The zeros of -2x^2-5x+6=0 are x=-(5+sqrt(73))/4 ,x=(sqrt(73)-5)/4

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- 2 x^{2} - 5 x + 6 = 0

x = - \frac{5 + 73}{4}, x = \frac{73 - 5}{4}

Decimal Notation

x = - 3.38600 \dots, x = 0.88600 \dots

Solution steps

- 2 x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 6 = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 73}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 73}{2 ( - 2 )} : - \frac{5 + 73}{4}

x = \frac{- ( - 5 ) - 73}{2 ( - 2 )} : \frac{73 - 5}{4}

The solutions to the quadratic equation are:

x = - \frac{5 + 73}{4}, x = \frac{73 - 5}{4}

3 x^{2} + 3 x - 126 = 0

11 x = - x^{2} - 24

(4 x - 3)^{2} = 44

k^{2} = 6 k

x^{2} - 20 = 5

What are the solutions to the equation -2x^2-5x+6=0 ?
The solutions to the equation -2x^2-5x+6=0 are x=-(5+sqrt(73))/4 ,x=(sqrt(73)-5)/4
Find the zeros of -2x^2-5x+6=0
The zeros of -2x^2-5x+6=0 are x=-(5+sqrt(73))/4 ,x=(sqrt(73)-5)/4