What are the solutions to the equation 0=x^2-6x+7 ?

The solutions to the equation 0=x^2-6x+7 are x=3+sqrt(2),x=3-sqrt(2)

Find the zeros of 0=x^2-6x+7

The zeros of 0=x^2-6x+7 are x=3+sqrt(2),x=3-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 6 x + 7

x = 3 + 2, x = 3 - 2

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

0 = x^{2} - 6 x + 7

Switch sides

x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

x_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

x = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

x = 3 + 2, x = 3 - 2

2 x^{2} = 10 x - 11

5 x^{2} = 25 x

3 x^{2} + 12 x + 13 = 0

y^{2} = 169

x^{2} - 5 x - 300 = 0

What are the solutions to the equation 0=x^2-6x+7 ?
The solutions to the equation 0=x^2-6x+7 are x=3+sqrt(2),x=3-sqrt(2)
Find the zeros of 0=x^2-6x+7
The zeros of 0=x^2-6x+7 are x=3+sqrt(2),x=3-sqrt(2)