What are the solutions to the equation 2x^2+14x-120=0 ?

The solutions to the equation 2x^2+14x-120=0 are x=5,x=-12

Find the zeros of 2x^2+14x-120=0

The zeros of 2x^2+14x-120=0 are x=5,x=-12

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2 x^{2} + 14 x - 120 = 0

x = 5, x = - 12

Solution steps

2 x^{2} + 14 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 (- 120) = 34

x_{1, 2} = \frac{- 14 \pm 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 14 + 34}{2 \cdot 2}, x_{2} = \frac{- 14 - 34}{2 \cdot 2}

x = \frac{- 14 + 34}{2 \cdot 2} : 5

x = \frac{- 14 - 34}{2 \cdot 2} : - 12

The solutions to the quadratic equation are:

x = 5, x = - 12

6 x^{2} = 3 x - 9

x, \frac{x ^{2}}{2} + \frac{y ^{2}}{3} + \frac{z ^{2}}{4} = 1

x^{2} = e^{4}

s^{2} - 2 s - 2 = 0

3 (x + 1)^{2} + 4 = 22

What are the solutions to the equation 2x^2+14x-120=0 ?
The solutions to the equation 2x^2+14x-120=0 are x=5,x=-12
Find the zeros of 2x^2+14x-120=0
The zeros of 2x^2+14x-120=0 are x=5,x=-12