What are the solutions to the equation 4x+x^2+12=0 ?

The solutions to the equation 4x+x^2+12=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

Find the zeros of 4x+x^2+12=0

The zeros of 4x+x^2+12=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

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4 x + x^{2} + 12 = 0

x = - 2 + 22 i, x = - 2 - 22 i

Solution steps

4 x + x^{2} + 12 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 12 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 1}

x = \frac{- 4 + 4 2 i}{2 \cdot 1} : - 2 + 22 i

x = \frac{- 4 - 4 2 i}{2 \cdot 1} : - 2 - 22 i

The solutions to the quadratic equation are:

x = - 2 + 22 i, x = - 2 - 22 i

15 x^{2} = - 5 x + 20

x^{2} - 36 x - 264 = 0

t^{2} - 3 t - 54 = 0

x (5 x + 19) = 4

2 x^{2} - 11 = - 9 x

What are the solutions to the equation 4x+x^2+12=0 ?
The solutions to the equation 4x+x^2+12=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i
Find the zeros of 4x+x^2+12=0
The zeros of 4x+x^2+12=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i