What are the solutions to the equation x^2+18x+18=-5 ?

The solutions to the equation x^2+18x+18=-5 are x=-9+sqrt(58),x=-9-sqrt(58)

Find the zeros of x^2+18x+18=-5

The zeros of x^2+18x+18=-5 are x=-9+sqrt(58),x=-9-sqrt(58)

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x^{2} + 18 x + 18 = - 5

x = - 9 + 58, x = - 9 - 58

Decimal Notation

x = - 1.38422 \dots, x = - 16.61577 \dots

Solution steps

x^{2} + 18 x + 18 = - 5

Move

5

to the left side

x^{2} + 18 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 23 = 258

x_{1, 2} = \frac{- 18 \pm 2 58}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 58}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 58}{2 \cdot 1}

x = \frac{- 18 + 2 58}{2 \cdot 1} : - 9 + 58

x = \frac{- 18 - 2 58}{2 \cdot 1} : - 9 - 58

The solutions to the quadratic equation are:

x = - 9 + 58, x = - 9 - 58

- 12 x^{2} - 30 x = 0

5 x^{2} + 7 x = 9

4 x + x^{2} = 12

- 5 (x - 3)^{2} = 10

x, 4 x^{2} - y^{2} + 16 (z - 2)^{2} = 100

What are the solutions to the equation x^2+18x+18=-5 ?
The solutions to the equation x^2+18x+18=-5 are x=-9+sqrt(58),x=-9-sqrt(58)
Find the zeros of x^2+18x+18=-5
The zeros of x^2+18x+18=-5 are x=-9+sqrt(58),x=-9-sqrt(58)