What are the solutions to the equation 0=-x^2+6x-8 ?

The solutions to the equation 0=-x^2+6x-8 are x=2,x=4

Find the zeros of 0=-x^2+6x-8

The zeros of 0=-x^2+6x-8 are x=2,x=4

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0 = - x^{2} + 6 x - 8

x = 2, x = 4

Solution steps

0 = - x^{2} + 6 x - 8

Switch sides

- x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 8) = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2}{2 ( - 1 )}

x = \frac{- 6 + 2}{2 ( - 1 )} : 2

x = \frac{- 6 - 2}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 2, x = 4

4 x^{2} - 10 x + 7 = 0

x^{2} = 0.16

x^{2} = 99

x^{2} = 94

s, t (s t^{2} + 2 t + s) d s + s^{2} (1 - t^{2}) d t = 0

What are the solutions to the equation 0=-x^2+6x-8 ?
The solutions to the equation 0=-x^2+6x-8 are x=2,x=4
Find the zeros of 0=-x^2+6x-8
The zeros of 0=-x^2+6x-8 are x=2,x=4