What are the solutions to the equation 0=3x^2+6x-24 ?

The solutions to the equation 0=3x^2+6x-24 are x=2,x=-4

Find the zeros of 0=3x^2+6x-24

The zeros of 0=3x^2+6x-24 are x=2,x=-4

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0 = 3 x^{2} + 6 x - 24

x = 2, x = - 4

Solution steps

0 = 3 x^{2} + 6 x - 24

Switch sides

3 x^{2} + 6 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 24) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 3}, x_{2} = \frac{- 6 - 18}{2 \cdot 3}

x = \frac{- 6 + 18}{2 \cdot 3} : 2

x = \frac{- 6 - 18}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

x^{2} - 2 x - x = 0

x^{2} - \frac{5}{2} x - \frac{3}{2} = 0

(x - 6)^{2} + 6 = 900

m^{2} + 26 m

5 x^{2} + 20 x + 18

What are the solutions to the equation 0=3x^2+6x-24 ?
The solutions to the equation 0=3x^2+6x-24 are x=2,x=-4
Find the zeros of 0=3x^2+6x-24
The zeros of 0=3x^2+6x-24 are x=2,x=-4