What are the solutions to the equation x^2+4(x-2)^2=4 ?

The solutions to the equation x^2+4(x-2)^2=4 are x=2,x= 6/5

Find the zeros of x^2+4(x-2)^2=4

The zeros of x^2+4(x-2)^2=4 are x=2,x= 6/5

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x^{2} + 4 (x - 2)^{2} = 4

x = 2, x = \frac{6}{5}

Decimal Notation

x = 2, x = 1.2

Solution steps

x^{2} + 4 (x - 2)^{2} = 4

Expand

x^{2} + 4 (x - 2)^{2} : 5 x^{2} - 16 x + 16

5 x^{2} - 16 x + 16 = 4

Move

4

to the left side

5 x^{2} - 16 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

(- 16)^{2} - 4 \cdot 5 \cdot 12 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 5}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 5}

x = \frac{- ( - 16 ) + 4}{2 \cdot 5} : 2

x = \frac{- ( - 16 ) - 4}{2 \cdot 5} : \frac{6}{5}

The solutions to the quadratic equation are:

x = 2, x = \frac{6}{5}

x, x^{2} - 6 x y + 9 y^{2} - 40 x - 80 y = 0

v^{2} - 10 v + 21 = 0

x^{2} + 10 x + 24

36 x^{2} - 24 = 0

(9 + y)^{2} + y^{2} = 305

What are the solutions to the equation x^2+4(x-2)^2=4 ?
The solutions to the equation x^2+4(x-2)^2=4 are x=2,x= 6/5
Find the zeros of x^2+4(x-2)^2=4
The zeros of x^2+4(x-2)^2=4 are x=2,x= 6/5