What are the solutions to the equation w^2+13w=20 ?

The solutions to the equation w^2+13w=20 are w=(-13+sqrt(249))/2 ,w=(-13-sqrt(249))/2

Find the zeros of w^2+13w=20

The zeros of w^2+13w=20 are w=(-13+sqrt(249))/2 ,w=(-13-sqrt(249))/2

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w^{2} + 13 w = 20

w = \frac{- 13 + 249}{2}, w = \frac{- 13 - 249}{2}

Decimal Notation

w = 1.38986 \dots, w = - 14.38986 \dots

Solution steps

w^{2} + 13 w = 20

Move

20

to the left side

w^{2} + 13 w - 20 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 20) = 249

w_{1, 2} = \frac{- 13 \pm 249}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 13 + 249}{2 \cdot 1}, w_{2} = \frac{- 13 - 249}{2 \cdot 1}

w = \frac{- 13 + 249}{2 \cdot 1} : \frac{- 13 + 249}{2}

w = \frac{- 13 - 249}{2 \cdot 1} : \frac{- 13 - 249}{2}

The solutions to the quadratic equation are:

w = \frac{- 13 + 249}{2}, w = \frac{- 13 - 249}{2}

y, x^{2} + y^{2} = 2 x y

5 x - 17 = (x + 3) (x - 3)

9 x = 4 - 2 x^{2}

3 m^{2} - 16 m - 2 = - 7

3 x^{2} - x^{2} = 1800

What are the solutions to the equation w^2+13w=20 ?
The solutions to the equation w^2+13w=20 are w=(-13+sqrt(249))/2 ,w=(-13-sqrt(249))/2
Find the zeros of w^2+13w=20
The zeros of w^2+13w=20 are w=(-13+sqrt(249))/2 ,w=(-13-sqrt(249))/2