What are the solutions to the equation 4x^2+7x-2=0 ?

The solutions to the equation 4x^2+7x-2=0 are x= 1/4 ,x=-2

Find the zeros of 4x^2+7x-2=0

The zeros of 4x^2+7x-2=0 are x= 1/4 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 7 x - 2 = 0

x = \frac{1}{4}, x = - 2

Decimal Notation

x = 0.25, x = - 2

Solution steps

4 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 2) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 4}, x_{2} = \frac{- 7 - 9}{2 \cdot 4}

x = \frac{- 7 + 9}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 7 - 9}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 2

12 x^{2} + 17 x + 6

2 (12 - 8 x) = x - 11 x

- i^{2}

3 x^{2} - 24 x = - 45

What are the solutions to the equation 4x^2+7x-2=0 ?
The solutions to the equation 4x^2+7x-2=0 are x= 1/4 ,x=-2
Find the zeros of 4x^2+7x-2=0
The zeros of 4x^2+7x-2=0 are x= 1/4 ,x=-2