What are the solutions to the equation 1/2 x^2-12=-37 ?

The solutions to the equation 1/2 x^2-12=-37 are x=sqrt(2)*5i,x=-sqrt(2)*5i

Find the zeros of 1/2 x^2-12=-37

The zeros of 1/2 x^2-12=-37 are x=sqrt(2)*5i,x=-sqrt(2)*5i

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\frac{1}{2} x^{2} - 12 = - 37

x = 2 \cdot 5 i, x = - 2 \cdot 5 i

Solution steps

\frac{1}{2} x^{2} - 12 = - 37

Move

12

to the right side

\frac{1}{2} x^{2} = - 25

Multiply both sides by

2

x^{2} = - 50

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 50, x = - - 50

- 50 = 2 \cdot 5 i

- - 50 = - 2 \cdot 5 i

x = 2 \cdot 5 i, x = - 2 \cdot 5 i

3 x^{2} - x + 17 = 17

2 x^{2} - 8 x - 64 = 0

\frac{3}{4} y^{2} - 3 = 18

5 v^{2} - 15 v = 0

r, (x - 0)^{2} + (y - 3)^{2} = r^{2}

What are the solutions to the equation 1/2 x^2-12=-37 ?
The solutions to the equation 1/2 x^2-12=-37 are x=sqrt(2)*5i,x=-sqrt(2)*5i
Find the zeros of 1/2 x^2-12=-37
The zeros of 1/2 x^2-12=-37 are x=sqrt(2)*5i,x=-sqrt(2)*5i