What are the solutions to the equation 30+40x-3x^2=0 ?

The solutions to the equation 30+40x-3x^2=0 are x=-(-20+7sqrt(10))/3 ,x=(20+7sqrt(10))/3

Find the zeros of 30+40x-3x^2=0

The zeros of 30+40x-3x^2=0 are x=-(-20+7sqrt(10))/3 ,x=(20+7sqrt(10))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

30 + 40 x - 3 x^{2} = 0

x = - \frac{- 20 + 7 10}{3}, x = \frac{20 + 7 10}{3}

Decimal Notation

x = - 0.71198 \dots, x = 14.04531 \dots

Solution steps

30 + 40 x - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 40 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 3 ) \cdot 30}{2 ( - 3 )}

4 0^{2} - 4 (- 3) \cdot 30 = 1410

x_{1, 2} = \frac{- 40 \pm 14 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 40 + 14 10}{2 ( - 3 )}, x_{2} = \frac{- 40 - 14 10}{2 ( - 3 )}

x = \frac{- 40 + 14 10}{2 ( - 3 )} : - \frac{- 20 + 7 10}{3}

x = \frac{- 40 - 14 10}{2 ( - 3 )} : \frac{20 + 7 10}{3}

The solutions to the quadratic equation are:

x = - \frac{- 20 + 7 10}{3}, x = \frac{20 + 7 10}{3}

\frac{1}{d ^{2}} = \frac{h ^{2} + k ^{2}}{a ^{2}} + \frac{l ^{2}}{c ^{2}}

8 x^{2} + 16 x + 3 = 0

x, x^{2} + y^{2} - 4 x - 2 y + 85 = 0

d, d^{2} y - 4 e^{5 x} = 0

4 x^{2} - 28 x + 43 = - 2

What are the solutions to the equation 30+40x-3x^2=0 ?
The solutions to the equation 30+40x-3x^2=0 are x=-(-20+7sqrt(10))/3 ,x=(20+7sqrt(10))/3
Find the zeros of 30+40x-3x^2=0
The zeros of 30+40x-3x^2=0 are x=-(-20+7sqrt(10))/3 ,x=(20+7sqrt(10))/3