What are the solutions to the equation c^2+5(5-c)=22 ?

The solutions to the equation c^2+5(5-c)=22 are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2

Find the zeros of c^2+5(5-c)=22

The zeros of c^2+5(5-c)=22 are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2

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c^{2} + 5 (5 - c) = 22

c = \frac{5 + 13}{2}, c = \frac{5 - 13}{2}

Decimal Notation

c = 4.30277 \dots, c = 0.69722 \dots

Solution steps

c^{2} + 5 (5 - c) = 22

Expand

c^{2} + 5 (5 - c) : c^{2} + 25 - 5 c

c^{2} + 25 - 5 c = 22

Move

22

to the left side

c^{2} - 5 c + 3 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 3 = 13

c_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, c_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

c = \frac{- ( - 5 ) + 13}{2 \cdot 1} : \frac{5 + 13}{2}

c = \frac{- ( - 5 ) - 13}{2 \cdot 1} : \frac{5 - 13}{2}

The solutions to the quadratic equation are:

c = \frac{5 + 13}{2}, c = \frac{5 - 13}{2}

3 x^{2} - 28 x + 56 = 7

2.25 x^{2} - 3 x = - 1

(x + 3)^{2} = 3 x

x^{2} + 7^{2} = 9^{2}

x^{2} + x - 6 = 0

What are the solutions to the equation c^2+5(5-c)=22 ?
The solutions to the equation c^2+5(5-c)=22 are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2
Find the zeros of c^2+5(5-c)=22
The zeros of c^2+5(5-c)=22 are c=(5+sqrt(13))/2 ,c=(5-sqrt(13))/2