What are the solutions to the equation 43m^2+14m=-1 ?

The solutions to the equation 43m^2+14m=-1 are m=(-7+sqrt(6))/(43),m=-(7+sqrt(6))/(43)

Find the zeros of 43m^2+14m=-1

The zeros of 43m^2+14m=-1 are m=(-7+sqrt(6))/(43),m=-(7+sqrt(6))/(43)

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43 m^{2} + 14 m = - 1

m = \frac{- 7 + 6}{43}, m = - \frac{7 + 6}{43}

Decimal Notation

m = - 0.10582 \dots, m = - 0.21975 \dots

Solution steps

43 m^{2} + 14 m = - 1

Move

1

to the left side

43 m^{2} + 14 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 43 \cdot 1}{2 \cdot 43}

1 4^{2} - 4 \cdot 43 \cdot 1 = 26

m_{1, 2} = \frac{- 14 \pm 2 6}{2 \cdot 43}

Separate the solutions

m_{1} = \frac{- 14 + 2 6}{2 \cdot 43}, m_{2} = \frac{- 14 - 2 6}{2 \cdot 43}

m = \frac{- 14 + 2 6}{2 \cdot 43} : \frac{- 7 + 6}{43}

m = \frac{- 14 - 2 6}{2 \cdot 43} : - \frac{7 + 6}{43}

The solutions to the quadratic equation are:

m = \frac{- 7 + 6}{43}, m = - \frac{7 + 6}{43}

x^{2} + 7^{2} = 1 1^{2}

4 s^{2} + 12 s + 9 = 0

5 x^{2} + 9 x = 0

35 x^{2} + 22 x + 3 = 0

0 = x^{2} + x - 20

What are the solutions to the equation 43m^2+14m=-1 ?
The solutions to the equation 43m^2+14m=-1 are m=(-7+sqrt(6))/(43),m=-(7+sqrt(6))/(43)
Find the zeros of 43m^2+14m=-1
The zeros of 43m^2+14m=-1 are m=(-7+sqrt(6))/(43),m=-(7+sqrt(6))/(43)