What are the solutions to the equation 4x^2-72x+324=0 ?

The solutions to the equation 4x^2-72x+324=0 are x=9

Find the zeros of 4x^2-72x+324=0

The zeros of 4x^2-72x+324=0 are x=9

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4 x^{2} - 72 x + 324 = 0

x = 9

Solution steps

4 x^{2} - 72 x + 324 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 4 \cdot 324}{2 \cdot 4}

(- 72)^{2} - 4 \cdot 4 \cdot 324 = 0

x_{1, 2} = \frac{- ( - 72 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 72 )}{2 \cdot 4}

\frac{- ( - 72 )}{2 \cdot 4} = 9

x = 9

The solution to the quadratic equation is:

x = 9

v^{2} + 15 v + 11 = 5 v + 5

x^{2} - 5 x + 6 x = 0

(2 x - 7)^{3} = (2 x)^{3} - 7^{3}

\frac{1}{2} x^{2} - 7 x + 7 = 0

x^{2} - a x + 1 = 0

What are the solutions to the equation 4x^2-72x+324=0 ?
The solutions to the equation 4x^2-72x+324=0 are x=9
Find the zeros of 4x^2-72x+324=0
The zeros of 4x^2-72x+324=0 are x=9