What are the solutions to the equation 7-4t+t^2=0 ?

The solutions to the equation 7-4t+t^2=0 are t=2+sqrt(3)i,t=2-sqrt(3)i

Find the zeros of 7-4t+t^2=0

The zeros of 7-4t+t^2=0 are t=2+sqrt(3)i,t=2-sqrt(3)i

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7 - 4 t + t^{2} = 0

t = 2 + 3 i, t = 2 - 3 i

Solution steps

7 - 4 t + t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

t^{2} - 4 t + 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 7 : 23 i

t_{1, 2} = \frac{- ( - 4 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 1}, t_{2} = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 1}

t = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 1} : 2 + 3 i

t = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 1} : 2 - 3 i

The solutions to the quadratic equation are:

t = 2 + 3 i, t = 2 - 3 i

x^{2} + 11 x + 30 = 0

x^{2} - 12 = - x

[(2 - x) (- 6 - x) - 5 (- 3)] = 0

3 x^{2} - 5 = 4 x

x (x + 1) - 31 = 5 (2 x + 1)

What are the solutions to the equation 7-4t+t^2=0 ?
The solutions to the equation 7-4t+t^2=0 are t=2+sqrt(3)i,t=2-sqrt(3)i
Find the zeros of 7-4t+t^2=0
The zeros of 7-4t+t^2=0 are t=2+sqrt(3)i,t=2-sqrt(3)i