What are the solutions to the equation solvefor x,x^2+8x-9=0 ?

The solutions to the equation solvefor x,x^2+8x-9=0 are x=1,x=-9

Find the zeros of solvefor x,x^2+8x-9=0

The zeros of solvefor x,x^2+8x-9=0 are x=1,x=-9

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x, x^{2} + 8 x - 9 = 0

x = 1, x = - 9

Solution steps

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

x, 16 x^{2} - 96 x - 9 y^{2} + 18 y + 135 = 0

2 x^{2} + 5 x + 20 = 0

a^{2} + 3^{2} = 6^{2}

7 x^{2} - 8 x + 2 = 0

(x - 1) (x - 3) = 2 x^{2} - 9

What are the solutions to the equation solvefor x,x^2+8x-9=0 ?
The solutions to the equation solvefor x,x^2+8x-9=0 are x=1,x=-9
Find the zeros of solvefor x,x^2+8x-9=0
The zeros of solvefor x,x^2+8x-9=0 are x=1,x=-9