What are the solutions to the equation 16x^2+24x+5=0 ?

The solutions to the equation 16x^2+24x+5=0 are x=-1/4 ,x=-5/4

Find the zeros of 16x^2+24x+5=0

The zeros of 16x^2+24x+5=0 are x=-1/4 ,x=-5/4

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16 x^{2} + 24 x + 5 = 0

x = - \frac{1}{4}, x = - \frac{5}{4}

Decimal Notation

x = - 0.25, x = - 1.25

Solution steps

16 x^{2} + 24 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 16 \cdot 5}{2 \cdot 16}

2 4^{2} - 4 \cdot 16 \cdot 5 = 16

x_{1, 2} = \frac{- 24 \pm 16}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 24 + 16}{2 \cdot 16}, x_{2} = \frac{- 24 - 16}{2 \cdot 16}

x = \frac{- 24 + 16}{2 \cdot 16} : - \frac{1}{4}

x = \frac{- 24 - 16}{2 \cdot 16} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{5}{4}

y, - 3 y^{2} z - 3 y z^{2} = 21

p^{2} + 14 p + 49 = 2

w^{2} + 16 w + 64 = 0

3 b^{2} - 6 b = 0

3 x^{2} - 81 = 0

What are the solutions to the equation 16x^2+24x+5=0 ?
The solutions to the equation 16x^2+24x+5=0 are x=-1/4 ,x=-5/4
Find the zeros of 16x^2+24x+5=0
The zeros of 16x^2+24x+5=0 are x=-1/4 ,x=-5/4