What are the solutions to the equation -3x^2+3x+60=0 ?

The solutions to the equation -3x^2+3x+60=0 are x=-4,x=5

Find the zeros of -3x^2+3x+60=0

The zeros of -3x^2+3x+60=0 are x=-4,x=5

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- 3 x^{2} + 3 x + 60 = 0

x = - 4, x = 5

Solution steps

- 3 x^{2} + 3 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 60}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 60 = 27

x_{1, 2} = \frac{- 3 \pm 27}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 27}{2 ( - 3 )}, x_{2} = \frac{- 3 - 27}{2 ( - 3 )}

x = \frac{- 3 + 27}{2 ( - 3 )} : - 4

x = \frac{- 3 - 27}{2 ( - 3 )} : 5

The solutions to the quadratic equation are:

x = - 4, x = 5

x^{2} - 15 x - 20 = 0

x^{2} - 6 = 43

g, 3 = N g^{2} - Q

t^{2} + 5 t - 6 = 0

6 x^{2} + 96 x + 378 = 0

What are the solutions to the equation -3x^2+3x+60=0 ?
The solutions to the equation -3x^2+3x+60=0 are x=-4,x=5
Find the zeros of -3x^2+3x+60=0
The zeros of -3x^2+3x+60=0 are x=-4,x=5