What are the solutions to the equation (10-2x)(20-2x)=96 ?

The solutions to the equation (10-2x)(20-2x)=96 are x=13,x=2

Find the zeros of (10-2x)(20-2x)=96

The zeros of (10-2x)(20-2x)=96 are x=13,x=2

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(10 - 2 x) (20 - 2 x) = 96

x = 13, x = 2

Solution steps

(10 - 2 x) (20 - 2 x) = 96

Expand

(10 - 2 x) (20 - 2 x) : 200 - 60 x + 4 x^{2}

200 - 60 x + 4 x^{2} = 96

Move

96

to the left side

4 x^{2} - 60 x + 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 4 \cdot 104}{2 \cdot 4}

(- 60)^{2} - 4 \cdot 4 \cdot 104 = 44

x_{1, 2} = \frac{- ( - 60 ) \pm 44}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 44}{2 \cdot 4}, x_{2} = \frac{- ( - 60 ) - 44}{2 \cdot 4}

x = \frac{- ( - 60 ) + 44}{2 \cdot 4} : 13

x = \frac{- ( - 60 ) - 44}{2 \cdot 4} : 2

The solutions to the quadratic equation are:

x = 13, x = 2

3 - 7 z \leq - 18

n^{2} + 14 nm + 33 m^{2}

9 - 16 x^{2}

8 (y + 4) = 7 y + 38

3 x^{2} - x - 14

What are the solutions to the equation (10-2x)(20-2x)=96 ?
The solutions to the equation (10-2x)(20-2x)=96 are x=13,x=2
Find the zeros of (10-2x)(20-2x)=96
The zeros of (10-2x)(20-2x)=96 are x=13,x=2