What are the solutions to the equation 4x^2-24x+35=0 ?

The solutions to the equation 4x^2-24x+35=0 are x= 7/2 ,x= 5/2

Find the zeros of 4x^2-24x+35=0

The zeros of 4x^2-24x+35=0 are x= 7/2 ,x= 5/2

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4 x^{2} - 24 x + 35 = 0

x = \frac{7}{2}, x = \frac{5}{2}

Decimal Notation

x = 3.5, x = 2.5

Solution steps

4 x^{2} - 24 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 35}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 35 = 4

x_{1, 2} = \frac{- ( - 24 ) \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 4}{2 \cdot 4}

x = \frac{- ( - 24 ) + 4}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 24 ) - 4}{2 \cdot 4} : \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{5}{2}

t^{2} + 2 = 0

2 x^{2} - x + 55 = x^{2} + 10 x + 25

x^{2} + (x + 1)^{2} = 145

x^{2} + (x + 6)^{2} = 260

x, y^{2} = 3 x^{2}

What are the solutions to the equation 4x^2-24x+35=0 ?
The solutions to the equation 4x^2-24x+35=0 are x= 7/2 ,x= 5/2
Find the zeros of 4x^2-24x+35=0
The zeros of 4x^2-24x+35=0 are x= 7/2 ,x= 5/2