What are the solutions to the equation x^2+100=29x ?

The solutions to the equation x^2+100=29x are x=25,x=4

Find the zeros of x^2+100=29x

The zeros of x^2+100=29x are x=25,x=4

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x^{2} + 100 = 29 x

x = 25, x = 4

Solution steps

x^{2} + 100 = 29 x

Move

29 x

to the left side

x^{2} + 100 - 29 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 29 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 29)^{2} - 4 \cdot 1 \cdot 100 = 21

x_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 1}, x_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 1}

x = \frac{- ( - 29 ) + 21}{2 \cdot 1} : 25

x = \frac{- ( - 29 ) - 21}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 25, x = 4

y^{2} + 3 y = 6 y + 10

4 x^{2} + 6 x + 8 = 0

3 x^{2} - 6 x = 5

x^{2} - 6 x - 5 = 2

x^{2} + (3 x - 10)^{2} = 100

What are the solutions to the equation x^2+100=29x ?
The solutions to the equation x^2+100=29x are x=25,x=4
Find the zeros of x^2+100=29x
The zeros of x^2+100=29x are x=25,x=4