What are the solutions to the equation x^2+17x+3=0 ?

The solutions to the equation x^2+17x+3=0 are x=(-17+sqrt(277))/2 ,x=(-17-sqrt(277))/2

Find the zeros of x^2+17x+3=0

The zeros of x^2+17x+3=0 are x=(-17+sqrt(277))/2 ,x=(-17-sqrt(277))/2

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x^{2} + 17 x + 3 = 0

x = \frac{- 17 + 277}{2}, x = \frac{- 17 - 277}{2}

Decimal Notation

x = - 0.17834 \dots, x = - 16.82165 \dots

Solution steps

x^{2} + 17 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 3 = 277

x_{1, 2} = \frac{- 17 \pm 277}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 277}{2 \cdot 1}, x_{2} = \frac{- 17 - 277}{2 \cdot 1}

x = \frac{- 17 + 277}{2 \cdot 1} : \frac{- 17 + 277}{2}

x = \frac{- 17 - 277}{2 \cdot 1} : \frac{- 17 - 277}{2}

The solutions to the quadratic equation are:

x = \frac{- 17 + 277}{2}, x = \frac{- 17 - 277}{2}

d, A = \frac{1}{2} d^{2}

132 - 92 x + 12 x^{2} = 0

- 2 x^{2} - 2 x - 3 = 0

x^{2} = \frac{99}{100}

x, (x + 1)^{2} + (y + 2)^{2} = 0

What are the solutions to the equation x^2+17x+3=0 ?
The solutions to the equation x^2+17x+3=0 are x=(-17+sqrt(277))/2 ,x=(-17-sqrt(277))/2
Find the zeros of x^2+17x+3=0
The zeros of x^2+17x+3=0 are x=(-17+sqrt(277))/2 ,x=(-17-sqrt(277))/2