What are the solutions to the equation 9x^2+4x^2=36 ?

The solutions to the equation 9x^2+4x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))

Find the zeros of 9x^2+4x^2=36

The zeros of 9x^2+4x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))

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9 x^{2} + 4 x^{2} = 36

x = \frac{6}{13}, x = - \frac{6}{13}

Decimal Notation

x = 1.66410 \dots, x = - 1.66410 \dots

Solution steps

9 x^{2} + 4 x^{2} = 36

Add similar elements:

9 x^{2} + 4 x^{2} = 13 x^{2}

13 x^{2} = 36

Divide both sides by

13

x^{2} = \frac{36}{13}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{36}{13}, x = - \frac{36}{13}

\frac{36}{13} = \frac{6}{13}

- \frac{36}{13} = - \frac{6}{13}

x = \frac{6}{13}, x = - \frac{6}{13}

2 (x + 4)^{2} = 242

18.82 = \frac{3 x ^{2}}{4}

2 (x - 1)^{2} = 90

(a + 4) x^{2} - 1 = (2 a + 2) x - a

n^{2} - n = - 41

What are the solutions to the equation 9x^2+4x^2=36 ?
The solutions to the equation 9x^2+4x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))
Find the zeros of 9x^2+4x^2=36
The zeros of 9x^2+4x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))